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-0.08x^2+2.88x=0
a = -0.08; b = 2.88; c = 0;
Δ = b2-4ac
Δ = 2.882-4·(-0.08)·0
Δ = 8.2944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.88)-\sqrt{8.2944}}{2*-0.08}=\frac{-2.88-\sqrt{8.2944}}{-0.16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.88)+\sqrt{8.2944}}{2*-0.08}=\frac{-2.88+\sqrt{8.2944}}{-0.16} $
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